Re^2: perl -n seemingly eating a line of input

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Re^3: perl -n seemingly eating a line of input by shmem (Chancellor) on May 01, 2017 at 13:18 UTC
...but also produces an extra line that is empty. That is due to your trailing `\n` and has nothing to do with the parenthesized `$_,<>` - compare `echo -e '55\n44\n33\n22\n11\n' \| perl -n -e '@a = ($_,<>); END{ print +@a; } ' echo -e '55\n44\n33\n22\n11' \| perl -n -e '@a = ($_,<>); END{ print @a +; } '` [download] - because `echo -e` will add a newline to its argument, so there are two of them, and thus an empty line. Use `echo -en` to suppress that: `echo -en '55\n44\n33\n22\n11\n' \| perl -n -e '@a = ($_,<>); END{ print + @a; } '` [download] perl -le'print map{pack c,($-++?1:13)+ord}split//,ESEL'	[reply] [d/l] [select]
Re^3: perl -n seemingly eating a line of input by bart (Canon) on May 01, 2017 at 13:00 UTC
Don't use `-n`, or change the way you process the lines: `echo -e '55\n44\n33\n22\n11\n' \| perl -n -e 'push @a, $_; END{ print @ +a; } '` [download] Explanation: `-n` makes perl loop through the input lines, and my code puts each line in turn onto the array. After all input is processed, I print out the array.	[reply] [d/l] [select]
Re^3: perl -n seemingly eating a line of input by Anonymous Monk on May 01, 2017 at 12:46 UTC
If you want to do `-e '@a=<>;'` and get all the lines, simply don't use `-n`.	[reply] [d/l] [select]


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