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Re^2: Converting 2**54-1 to Binary

by pryrt (Abbot)
on Mar 17, 2017 at 21:44 UTC ( [id://1185086]=note: print w/replies, xml ) Need Help??


in reply to Re: Converting 2**54-1 to Binary
in thread Converting 2**54-1 to Binary

Depends on the system: if you've got a 32-bit IV (perl -V:ivsize or perl -MConfig -le 'print $Config{ivsize}' will show 4 bytes for 32-bit, 8 bytes for 64-bit), then even that won't work, because it will overrun the 32-bit integer at 1<<32 - 1. And even with 64 bits, it will stop working above 64:

require v5.16; use Test::More qw(no_plan); for(51..66) {my $s = sprintf("%b", 1 << $_ -1); is length($s), $_, "1 << $_ -1"; } __END__ ok 1 - (1 << 51) -1 ok 2 - (1 << 52) -1 ok 3 - (1 << 53) -1 ok 4 - (1 << 54) -1 ok 5 - (1 << 55) -1 ok 6 - (1 << 56) -1 ok 7 - (1 << 57) -1 ok 8 - (1 << 58) -1 ok 9 - (1 << 59) -1 ok 10 - (1 << 60) -1 ok 11 - (1 << 61) -1 ok 12 - (1 << 62) -1 ok 13 - (1 << 63) -1 ok 14 - (1 << 64) -1 not ok 15 - (1 << 65) -1 # Failed test '(1 << 65) -1' # at - line 6. # got: '64' # expected: '65' not ok 16 - (1 << 66) -1 # Failed test '(1 << 66) -1' # at - line 6. # got: '64' # expected: '66' 1..16 # Looks like you failed 2 tests of 16.

So, philiprbrenan, "is this something to worry about?" depends on what you want to do. It's doing exactly what's expected for a double-float NV. And my example code does what's expected for a 64-bit integer. But as to whether that's behavior to worry about depends on what you're trying to do with your 2**$_n-1.

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