Re: Behaviour of unpack() with the Z template

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Re^2: Behaviour of unpack() with the Z template - 2nd attempt by johngg (Canon) on Feb 08, 2017 at 10:12 UTC
Thank you for the link. This line `['u', 'Z', "foo\0bar \0", "foo"]` [download] defines the test for an unpack using the 'Z' template and it would appear that a successful test would not leave a trailing null in the resultant string. I think this confirms that the expected behaviour is that the first null and everything to its right will be stripped. I think the use of "after" in Z strips everything after* the first null* is misleading and the wording should be clarified. Perhaps Z strips everything from the first null onwards would be a more accurate description. Cheers, JohnGG	[reply] [d/l]
Re^2: Behaviour of unpack() with the Z template by johngg (Canon) on Feb 07, 2017 at 23:32 UTC
Thank you for the link. This line `['u', 'Z', "foo\0bar \0", "foo"]` [download] defines the test for an unpack using the 'Z' template and it would appear that a successful test would not leave a trailing null in the resultant string. I think this confirms that the expected behaviour is that the first null and everything to its right will be stripped. I think the use of "after" in Z strips everything after* the first null* is misleading and the wording should be clarified. Perhaps Z strips everything from the first null onwards would be a more accurate description. Cheers, JohnGG	[reply] [d/l]


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