Take a look at File::Copy::Recursive

#!/usr/bin/perl
use strict;
use File::Copy::Recursive qw(dircopy dirmove);
use Time::Piece;

my $MDY = localtime->mdy('');
print "$MDY \n\n";

my $src  = 'e:/pervasive/staging/summit/';
my $dest = 'e:/pervasive/test/';

my @f = qw(01 02 03 04 05 06 07 08 30 
           40 41 42 43 44 44 50 80 85 99 );
           
my %compHash;
for my $n (@f[0]){ # replace with @f if it works for first
  $compHash{'C'.$n}         = 'APEX'.$n.'2015/C'.$n;
  $compHash{'C'.$n.'-2015'} = 'APEX'.$n.'2015/CSW';
};

foreach my $key (sort keys %compHash) {
  my $from = $src.$key;
  my $to   = $dest.$compHash{$key};
  print "Moving $from $to\n";
  dirmove ( $from,$to ) or die "$!"; 
}
[download]

I used the hash from this, ultimately. It worked perfectly. I try to stay away from hardcoding stuff as much as I can, but in this situation it was absolutely merited. The way you did this was perfect for me, and I so greatly appreciate your help with this.

How would I check to see if the file exists with this? So we have @f defined as the list of company numbers (C## - which represents company ID ) and for each of those, we're renaming the directory and moving it, but it breaks when it hits the key that does not exist in the folder (company 6 is not inside my zip, but it is a possible company that CAN be in the zip) so I'm looking for a quick way to check if the actual file, that corresponds with the key in our @f, even exists because if it doesn't, i need to skip it. I think this will involve next, or exists, or maybe both. Any insight?

see file exists test -e -X

foreach my $key (sort keys %compHash) {
   my $from = $src.$key;
   next unless (-e $from);
   .
   .
[download]

poj

Leetsauce,

You can test for file or directory by:

     if ( -f $file ) { .... }     ## $file is a file
     elsif  ( -d $file ) { ... }  ## also could use '_' for speed
     else { ,,, }                 ## Not what we're looking for
[download]

Good Luck...Ed