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Re: Re: problems with tr///;by $code or die (Deacon) |
on Sep 26, 2001 at 00:35 UTC ( [id://114672]=note: print w/replies, xml ) | Need Help?? |
s#\##g doesn't work. The substitution is incomplete. Tack another # on the end and see what happens:
You still need to escape the "\" regardless of what seperator you use. The # seperator is useful for "/" Simon Flack ($code or die) $,=reverse'"ro_';s,$,\$,;s,$,lc ref sub{},e;$, =~y'_"' ';eval"die";print $_,lc substr$@,0,3;
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