Re^2: why is my for loop using modulo giving me a weird output

first, I tried with five just to check out how modulo worked

nothing to do with even number yet. this is a incremental test code for me to learn perl code

I expected the output to look like this:

1 2 3 4

this is because as I go thru the for loop, I goes thru 1,2,3,4,5,6,7,8,9,10,...,15,...20

but the for loop returns "0" 1 2 3 4( not as expected with "0") then it gives me the same output another 4 times. I don't understand the output being given 4 times.

sorry for not being clearer

perhaps this helps explain my question on iteration

Comment on Re^2: why is my for loop using modulo giving me a weird output

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Re^3: why is my for loop using modulo giving me a weird output by afoken (Chancellor) on Jun 28, 2015 at 07:24 UTC
I tried with five just to check out how modulo worked https://en.wikipedia.org/wiki/Modulo_operation I expected the output to look like this: 1 2 3 4 Why? Modulo is the remainder of the division. 0 divided by 5 is 0, remaining 0. 1 divided by 5 is 0, remaining 1. 2 divided by 5 is 0, remaining 2. 3 divided by 5 is 0, remaining 3. 4 divided by 5 is 0, remaining 4. 5 divided by 5 is 1, remaining 0. 6 divided by 5 is 1, remaining 1. And so on. Alexander -- Today I will gladly share my knowledge and experience, for there are no sweeter words than "I told you so". ;-)	[reply]
Re^4: why is my for loop using modulo giving me a weird output by perlynewby (Scribe) on Jun 28, 2015 at 08:10 UTC
totally mistaken on modulo.my bad.. I get it and thank you! I guess , what I wanted to get out of this was the quotient NOT the remainder so if I divide the number 20 by 5, I want the quotient 4. ok, let me try this again then ,next step, is to write a program to find the smallest number that are evenly divided by all the given max_range numbers. ie: like 0-10. `use strict; use warnings; use integer; use constant number => 5; my %result; for ( my $i=0; $i<=20 ;$i++){ #my ($quo, $rem)= ($i/5, $i%5); #need to understand modulo #print "this is quotient",$quo,"when this is divident $i \n"; #print "this is remainder",$rem,"\n"; if ($i%5==0 && $i!=0){ print "this is the quotient",$i/5,"\n"; print "this is the divident",$i,"\n"; } }` [download]	[reply] [d/l]
Re^5: why is my for loop using modulo giving me a weird output by marinersk (Priest) on Jun 28, 2015 at 08:50 UTC
I think you might benefit from the use of `int`in order to chop off the fractional component for `$quo`.	[reply] [d/l] [select]
Re^6: why is my for loop using modulo giving me a weird output by perlynewby (Scribe) on Jun 28, 2015 at 09:51 UTC
Re^7: why is my for loop using modulo giving me a weird output by ww (Archbishop) on Jun 28, 2015 at 11:35 UTC
Re^7: why is my for loop using modulo giving me a weird output by marinersk (Priest) on Jun 29, 2015 at 14:29 UTC
Re^3: why is my for loop using modulo giving me a weird output by 2teez (Vicar) on Jun 28, 2015 at 07:16 UTC
Please read Corion again! Is there difference between printing, what modulo operator returns and using it to test? i.e `print 4%2; # or if (4%2 == 0) { # blah..blah... }` [download] Is there a difference? If you tell me, I'll forget. If you show me, I'll remember. if you involve me, I'll understand. --- Author unknown to me	[reply] [d/l]
Re^4: why is my for loop using modulo giving me a weird output by perlynewby (Scribe) on Jun 28, 2015 at 08:22 UTC
print, you are performing the task print while when you use IF then you are checking to see if the statement is true or false, If true then go and do what's inside the brackets. False, then don't go inside the brackets	[reply]


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