Re^2: How to interpolate CONSTANTS in Here docs?

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Re^3: How to interpolate CONSTANTS in Here docs? by BrowserUk (Patriarch) on Feb 11, 2015 at 23:16 UTC
Anonymonk has explained the syntax; but I thought I'd add that I'm not keen on doing it that way. Personally I prefer: `#! perl -slw use strict; use constant { OUT_DIR => 'out', OUT_FIELDSEP => '=', OUT_FILENAME => 'ks', OUT_SUFXSTOR => 'storable', VAL_MIN => 15, VAL_MAX => 3600, }; printf <<USAGE, OUT_DIR, OUT_FILENAME, OUT_SUFXSTOR, OUT_FIELDSEP, VAL +_MIN, VAL_MAX; This program does this and that with the %s. The filename is %s and the file suffix is %s. Fields are separated with the %s character. Enter a value between %s and %s. USAGE` [download] With the rise and rise of 'Social' network sites: 'Computers are making people easier to use everyday' Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error. "Science is about questioning the status quo. Questioning authority". I'm with torvalds on this In the absence of evidence, opinion is indistinguishable from prejudice. Agile (and TDD) debunked	[reply] [d/l]
Re^3: How to interpolate CONSTANTS in Here docs? by Anonymous Monk on Feb 11, 2015 at 22:49 UTC
`[...]` builds a reference to an anonymous array, which is in turn de-referenced by `@{...}`. It's roundabout, but necessary in this case because the constants built by constant are actually functions, like `sub OUT_DIR () { 'out' }`, and a function call like `OUT_DIR()` (or `OUT_DIR`) isn't interpolated in strings, while scalars (`$foo`) and arrays (`@bar`) are, including dereferenced arrayrefs (`@{$arrayref}` - see e.g. Using References).	[reply] [d/l] [select]
Re^3: How to interpolate CONSTANTS in Here docs? by shmem (Chancellor) on Feb 14, 2015 at 22:09 UTC
I'm not understanding the @{[]} syntax, although I do recognize the array index [], the hash {}, and the array @ -- can you explain what is going on, please? The array index isn't an array index, the hash isn't a hash. `@{ }` dereferences an array reference. `${ }` dereferences a scalar reference. `[ ]` constructs an array refrence, `\` constructs a scalar reference. So, instead of writing `This program does this and that with the @{[OUT_DIR]}. The filename is @{[OUT_FILENAME]} and the file suffix is @{[OUT_SUFXSTOR]}. Fields are separated with the @{[OUT_FIELDSEP]} character. Enter a val +ue between @{[VAL_MIN]} and @{[VAL_MAX]}.` [download] as in BrowserUk's example, you could also write `This program does this and that with the ${\OUT_DIR}. The filename is ${\OUT_FILENAME} and the file suffix is ${\OUT_SUFXSTOR}. Fields are separated with the ${\OUT_FIELDSEP} character. Enter a valu +e between ${\VAL_MIN} and ${\VAL_MAX}.` [download] The reference implementation in perl is the author's way of introducing ásbestos gélōs into the language, great fun and a good opportunity to distinguish yourself with expertise, once you grok cause and syntax. Quick, what does `~@~` mean? perl -le'print map{pack c,($-++?1:13)+ord}split//,ESEL'	[reply] [d/l] [select]
Re^3: How to interpolate CONSTANTS in Here docs? by ikegami (Patriarch) on Feb 16, 2015 at 02:15 UTC
If you spread it out, `"foo @{[ F ]} bar"` [download] you get `my @anon_array = F; my $anon_ref = \@anon_array; "foo @{ $anon_ref } bar"` [download] As you can see, `@BLOCK` (`@{ STATEMENTS }`) is an array dereference, not "a hash". `[ LIST ]` is an array constructor, not "an array index". It creates an array, assigns the result of `LIST`, and returns a reference to that array.	[reply] [d/l] [select]


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