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Re^3: What's the point of this 'overload' idiom?

by stevieb (Canon)
on Dec 07, 2022 at 07:33 UTC ( #11148643=note: print w/replies, xml ) Need Help??

in reply to Re^2: What's the point of this 'overload' idiom?
in thread What's the point of this 'overload' idiom?


Is a lazy man's way of saying:

sub thing { my ($self) = @_; return $self->name; }

In other words, it's a quick way of not declaring the 'self' variable. I do it a different way if I have a one line sub:

sub name { return $_[0]->{name}; }

...the following is equivalent:

sub name { return shift->{name}; }

When a Perl method receives its parameters, the first one is always the calling object. shift or $_[0] is the same thing; the object itself. If a method is more than one line, I prefer to collect the parameter as self (eg. my ($self) = @_;). That's not always the case.

Note that shift->thing; only works once... once you've shifted the object off the stack, you can't call shift again. In these cases, $_[0] is better, but if you have to use $_[0] more than once, you're far better off for self-documenting purposes to use my ($self) = @_;.

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