I'd like to know the name of each file as it is processed when fed into a scrip as run-time arguments.

perl -MEnglish -a -n -e 'print $F[0],"\n";' *.tab
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Say there were five files, a.tab, b.tab, c.tab, d.tab, and e.tab. That script cycles through each on, printing them line by line. How can I find the name of the currently open file? Is there a default filehandle variable or something? I couldn't find any mention of such in the perlvar(1) manual page.