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Re^3: Matching a string in a parenthesized block (regex help)

by LanX (Saint)
on Mar 06, 2021 at 01:34 UTC ( [id://11129183]=note: print w/replies, xml ) Need Help??


in reply to Re^2: Matching a string in a parenthesized block (regex help)
in thread Matching a string in a parenthesized block (regex help)

Look at my regex, I made both .*? non-greedy.

jwkrahn's solution isn't bad either, if your records are that consistent.

Edit

Though [^}]*? is certainly better for more complex input.

Cheers Rolf
(addicted to the Perl Programming Language :)
Wikisyntax for the Monastery

Replies are listed 'Best First'.
Re^4: Matching a string in a parenthesized block (regex help)
by maxamillionk (Acolyte) on Mar 06, 2021 at 14:02 UTC

    Sorry I should have clarified a bit more. Here is an example file I'm working with.

    ASDF_ONE { magic tmp tmp } ASDF_TWO { tmp tmp tmp } string3 { tmp tmp magic }

    Some sections have a common prefix, like ASDF_. I want a function in my program to scan a specific section for the magic word using an argument. The function returns true if word is found, else returns false. See code below for how I want to structure this:

    use warnings; use strict; my $file = "/path/to/file.txt"; sub has_word { my $arg = $_[0]; local $/; open FILE, '<', $file; while ( <FILE> ) { if ( m/(ASDF_$arg \{)(.*?)magic(.*?)(\})/s ) { close FILE; return 1; } else { close FILE; return 0; } } } sub main { if (has_word("ONE")) { print "ONE already has the word.\n"; } else { print "ONE does not have the word.\n"; } if (has_word("TWO")) { print "TWO already has the word.\n"; } else { print "TWO does not have the word.\n"; } } main;

    The output I get is:

    ONE already has the word. TWO already has the word.

    I think this .*? is searching for any character including the closing brace }.

      > s .*? is searching for any character including the closing brace }.

      Yes, that's why I added an alternative.

      Cheers Rolf
      (addicted to the Perl Programming Language :)
      Wikisyntax for the Monastery

        Thanks I think I got the right regex now, this seems to work

        m/(ASDF_$arg \{)([^}]*?)magic(.*?)(\})/s

        That is exactly what I wanted.

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