Win8 Strawberry 5.8.9.5 (32)  Thu 12/17/2020 21:09:41
C:\@Work\Perl\monks
>perl -Mstrict -Mwarnings -MData::Dump=dd
my $s = " info

                    John




                100 - 2000




                  Kent";

my $word = '';

while ($s =~ m{ $word [^[:alnum:]]+ ([[:alnum:]]+) }xms) {
    print "next word after '$word' is '$1' \n";
    $word = $1;
    }

print "another way \n";
my @words = $s =~ m{ [[:alnum:]]+ }xmsg;
dd \@words;
^Z
next word after '' is 'info'
next word after 'info' is 'John'
next word after 'John' is '100'
next word after '100' is '2000'
next word after '2000' is 'Kent'
another way
["info", "John", 100, 2000, "Kent"]
[download]

Update 1: The first method above will fail to capture 'info' if there are no "non-word" (whitespace in this case) characters before the first word in the string. To capture the first word in this case, use
    $s =~ m{ $word [^[:alnum:]]* ([[:alnum:]]+) }xms
(note * quantifier on [^[:alnum:]]* vice +).
However, using $word as an anchor then fails if there is a repeated "word" in the string: try replacing "100" with another instance of "info" and see what happens. IMHO, "another way" is the better way to strip out "words" from a string.

Update 2: Here's a way to loop through the string word-by-word regardless of leading/trailing whitespace or repeated words (but I still prefer stripping/extracting all words to an explicit or implicit array - the second method above):

Win8 Strawberry 5.8.9.5 (32)  Thu 12/17/2020 21:59:18
C:\@Work\Perl\monks
>perl -Mstrict -Mwarnings
my $s = " info

                    John


                info - 2000


                  Kent  ";

my $word;

while ($s =~ m{ [^[:alnum:]]* ([[:alnum:]]+) }xmsg) {
  if (defined $word) {
    print "next word after '$word' is '$1' \n";
    }
  else {
    print "first word is '$1' \n";
    }
  $word = $1;
  }
^Z
first word is 'info'
next word after 'info' is 'John'
next word after 'John' is 'info'
next word after 'info' is '2000'
next word after '2000' is 'Kent'
[download]