in reply to int() function
Perl does an internal magic error correction/guessing when printing a number like 195.999999...etc to compensate rounding errors on the last digits. (This of course in binary and not decimal representation)
I think that's why it prints $x1 as 196.
I'll check as soon my laptop is up and running.
update
as I thought, it's compensating the rounding error from not being able to accurately represent 0.15 in a based 2 floating number:
DB<28> $x1 = (1.15*170)+0.50; DB<29> printf("%.20f",$x1) 195.99999999999997000000 DB<30> printf("%.20f",0.15) 0.14999999999999999000 DB<31>
There is an easy workaround , avoid the decimal point when calculating and divide at the very end.
DB<35> $x1 = (115*170)+50; # no fractions DB<36> $x1 /=100 DB<37> p "$x1 = ",int $x1 196 = 196 DB<38>
see also Humans have too many fingers
Cheers Rolf
(addicted to the Perl Programming Language :)
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