Re^8: How the auto-increment operator works?

Replies are listed 'Best First'.
Re^9: How the auto-increment operator works? by LanX (Saint) on Aug 02, 2020 at 02:13 UTC
> > > If a new position is needed it'll adjust to the leftmost group. > my $foo = "Zz"; print ++$foo; prints "AAa" The A is a new position the next position to the right - which is causing the "carry" - is an uppercase character A. > when one "z" character is incremented it produces "aa". Again the left a is a new position, and the position to the right is a lowercase character. Cheers Rolf _{(addicted to the Perl Programming Language :) Wikisyntax for the Monastery}	[reply]
Re^10: How the auto-increment operator works? by AnomalousMonk (Archbishop) on Aug 02, 2020 at 02:45 UTC
... I'm not trolling ... Hmmm... Starting to question this. Give a man a fish: `<%-{-{-{-<`	[reply] [d/l]
Re^10: How the auto-increment operator works? by zapdos (Sexton) on Aug 02, 2020 at 03:17 UTC
"The A is a new position the next position to the right - which is causing the "carry" - is an uppercase character." "Again the left a is a new position, and the position to the right is a lowercase character." I don't get either. This is killing me inside. And AnomalousMonk, no, I'm not trolling I swear for God.	[reply]
Re^11: How the auto-increment operator works? by AnomalousMonk (Archbishop) on Aug 02, 2020 at 07:27 UTC
Perhaps the best thing to do is to remember that in "magic" string incrementation, digit/lowercase/uppercase characters increment from right to left, wrap within themselves, and generate a "carry" into the next left column (or a new left column character if it's already the leftmost (update: and see LanX's reply concerning the "type" of a new column)) when they wrap: `increment left col ("carry") <- '0' -> '1' -> .. '9' (digits) ^ \| \| \| +----------------+ increment left col ("carry") <- 'a' -> 'b' -> .. 'z' (lower case) ^ \| \| \| +----------------+ increment left col ("carry") <- 'A' -> 'B' -> .. 'Z' (upper case) ^ \| \| \| +----------------+` [download] String incrementation is pretty stable. I've never known it to change and I doubt it ever will (to preserve backward compatibility), so the best thing I can suggest is to experiment. Whatever results you get are the way "magic" string incrementation works. c:\@Work\Perl\monks>perl -e "my $s = 'zZ9'; print qq{'$s' -> }; ++$s +; print qq{'$s'};" 'zZ9' -> 'aaA0' c:\@Work\Perl\monks>perl -e "my $s = 'Zz9'; print qq{'$s' -> }; ++$s +; print qq{'$s'};" 'Zz9' -> 'AAa0' c:\@Work\Perl\monks>perl -e "my $s = 'Zzzz9'; print qq{'$s' -> }; ++ +$s; print qq{'$s'};" 'Zzzz9' -> 'AAaaa0' c:\@Work\Perl\monks>perl -e "my $s = 'zzzz9'; print qq{'$s' -> }; ++ +$s; print qq{'$s'};" 'zzzz9' -> 'aaaaa0' c:\@Work\Perl\monks>perl -e "my $s = 'ZZZZ9'; print qq{'$s' -> }; ++ +$s; print qq{'$s'};" 'ZZZZ9' -> 'AAAAA0' [download] Give a man a fish: `<%-{-{-{-<`	[reply] [d/l] [select]
Re^12: How the auto-increment operator works? by LanX (Saint) on Aug 02, 2020 at 16:02 UTC
Re^13: How the auto-increment operator works? by zapdos (Sexton) on Aug 02, 2020 at 23:26 UTC
Re^12: How the auto-increment operator works? by zapdos (Sexton) on Aug 02, 2020 at 07:48 UTC
Re^11: How the auto-increment operator works? by LanX (Saint) on Aug 02, 2020 at 13:59 UTC
> "The A is a new position the next position to the right - which is causing the "carry" - is an uppercase character." > I don't get either Please see Carry (arithmetic) Cheers Rolf _{(addicted to the Perl Programming Language :) Wikisyntax for the Monastery}	[reply]


more useful options
	PerlMonks