Re^4: Split a column

Now i am counting the values in the third column i.e how many up words how many down words and how many NA. For that i wrote the following program:

@values = values(%hash);

for $element (@values){
 if ($element =~ /up/){
    $sumA++; 
}if(($element =~ /down/)){
    $sumB++
}if(($element =~ /NA/)){
    $sumC++
}
}
print "Number of up is: $sumA\n";
print "Number of down is: $sumB\n";
print "Number of NA is: $sumC\n";
[download]

it is doing a great job but when i add a same row in the last of the file it doesn't count its up, down or NA word. why is that?

Comment on Re^4: Split a column Download Code

Replies are listed 'Best First'.
Re^5: Split a column by Fletch (Bishop) on Apr 13, 2020 at 18:03 UTC
Presuming you mean that you're adding a row which duplicates the key and value from another row you're not going to change your hash. If you've seen a key "foo" with a value "up", setting `$hash{ "foo" } = "up"` again doesn't really change anything in `%hash`. Hashes are unordered and maintain a single value for each key slot. If you need the count of rows with a particular value then count them as you read things. `my %counts_per_value; [... inside your while loop ...] $hash{ $first } = $third; $counts_per_value{ $third }++; [...] for my $value ( sort keys %counts_per_value ) { say qq{$value => $counts_per_value{ $value }; }` [download] The cake is a lie. The cake is a lie. The cake is a lie.	[reply] [d/l] [select]
Re^5: Split a column by choroba (Cardinal) on Apr 13, 2020 at 18:00 UTC
Because the hash contains each key just once. `map{substr$_->[0],$_->[1]\|\|0,1}[\\|\|{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^ARGV,3]`	[reply] [d/l]
Re^5: Split a column by AnomalousMonk (Archbishop) on Apr 13, 2020 at 18:44 UTC
You seem to misunderstand or lack understanding of the behavior of hashes, or associative arrays to use their formal name. Please see the discussions of keys, values and each in the Perl documentation. Give a man a fish: `<%-{-{-{-<`	[reply] [d/l]


Keep It Simple, Stupid
	PerlMonks