Re: 'xor' operator is not a sibling to 'or' and 'and'?

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Re^2: 'xor' operator is not a sibling to 'or' and 'and'? by rsFalse (Chaplain) on Dec 18, 2019 at 20:43 UTC
>> TRUE XOR TRUE = FALSE, so 2 xor 3 can't possibly return 3. But in the same way 'and' operator does not output '1', despite TRUE AND TRUE = TRUE.	[reply]
Re^3: 'xor' operator is not a sibling to 'or' and 'and'? by Fletch (Bishop) on Dec 18, 2019 at 21:04 UTC
`and` and `or` return the last expression evaluated; `xor` always evaluates both sides and then returns the exclusive or of those two expressions (not either of the surrounding expressions) so it's always going to be a boolean value either 1 or `''/0`. See perlop Update: On further reflection I think I see what your expectations for the behavior might be based on `and/or`'s behavior: if `A xor B` is true return whichever of A or B was true, otherwise return false. The cake is a lie. The cake is a lie. The cake is a lie.	[reply] [d/l] [select]
Re^4: 'xor' operator is not a sibling to 'or' and 'and'? by rsFalse (Chaplain) on Dec 18, 2019 at 21:11 UTC
In perlop I find that 'Binary "and" returns the logical conjunction of the two surrounding expressions.', not 'the last expression evaluated'. So maybe I misinterpret here? Or maybe text of docs here needs to be improved.	[reply]
Re^5: 'xor' operator is not a sibling to 'or' and 'and'? by Fletch (Bishop) on Dec 18, 2019 at 21:23 UTC
Re^6: 'xor' operator is not a sibling to 'or' and 'and'? by rsFalse (Chaplain) on Dec 18, 2019 at 21:35 UTC
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Re^3: 'xor' operator is not a sibling to 'or' and 'and'? by LanX (Saint) on Dec 19, 2019 at 05:24 UTC
> But in the same way `and` operator does not output '1', despite TRUE AND TRUE = TRUE. That's the feature of short circuit `and` and `or` which can't be replicated with `xor` Grandfather and ikegami already explained it perfectly. Cheers Rolf _{(addicted to the Perl Programming Language :) Wikisyntax for the Monastery FootballPerl is like chess, only without the dice}	[reply] [d/l]
Re^4: 'xor' operator is not a sibling to 'or' and 'and'? by rsFalse (Chaplain) on Dec 19, 2019 at 07:56 UTC
>> Binary "and" returns the logical conjunction of the two surrounding expressions. It's not much about short-circuit, but more about logical return value? I understand 'logical' as being Boolean, i.e. 1 or ''/0. So if an operator doesn't return a boolean value then this should be emphasized, and the sentence about return value rather should be corrected.	[reply]
Re^5: 'xor' operator is not a sibling to 'or' and 'and'? by soonix (Canon) on Dec 19, 2019 at 09:36 UTC
Re^5: 'xor' operator is not a sibling to 'or' and 'and'? by LanX (Saint) on Dec 19, 2019 at 14:41 UTC
Re^6: 'xor' operator is not a sibling to 'or' and 'and'? by rsFalse (Chaplain) on Dec 28, 2019 at 14:03 UTC
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Re^3: 'xor' operator is not a sibling to 'or' and 'and'? by ikegami (Patriarch) on Dec 19, 2019 at 20:17 UTC
No, that's completely wrong. The reason `$TRUE and $TRUE` doesn't necessarily return `1` has nothing to do with why `$TRUE xor $TRUE` doesn't return `1`. `$TRUE and $TRUE` doesn't necessarily return `1` because it's more useful to return its RHS. `$TRUE xor $TRUE` doesn't return `1` because that would be wrong.	[reply] [d/l] [select]


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