Re: Clean log

I'm interested to get the log10 of a whole number

(IIRC) Unless that number is a power of ten, the log10 is going to be irrational. This mean you wouldn't even be able to get an exact value by using Rationals (that's the definition). Best you can do to have an "exact value" would be something like:

sub log10 { 
  sprintf("%e", $_[0]); 
  print "log10($_[0]) = $2 + log10($1)" 
}
[download]

where you can drop the right side of the addition when $1 == 1.0. Oh and the right side is guaranteed to be in [0;1)

Edit: I suppose POSIX's log10, as demonstrated by pryrt does give the correct answer for the special cases that are powers of ten. But it's still going to give an approximation for all other numbers.

Comment on Re: Clean log_10 ? Download Code

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Re^2: Clean log_10 ? by LanX (Saint) on Nov 28, 2019 at 17:15 UTC
> > I'm interested to get the log10 of a whole number > the log10 is going to be irrational Yeah you're right. Rewording: I need the correct int(log10) to reproduce the E notation of a whole number. Cheers Rolf _{(addicted to the Perl Programming Language :) Wikisyntax for the Monastery FootballPerl is like chess, only without the dice}	[reply]
Re^3: Clean log_10 ? by dave_the_m (Monsignor) on Nov 28, 2019 at 19:48 UTC
Do you mean that the number you are taking the log of will always be a power of 10? In which case, the log will be almost an integer, so round to nearest int: `$power = int($log10 + 0.5);` Otherwise, why not use `sprintf "%e", $num` or similar? Dave.	[reply] [d/l] [select]
Re^4: Clean log_10 ? by LanX (Saint) on Nov 28, 2019 at 20:17 UTC
Here the context Re: More elegant way than multiple "if"? I didn't want 1TB to be listed as 1000GB. But the POSIX solution is quite good. Cheers Rolf _{(addicted to the Perl Programming Language :) Wikisyntax for the Monastery FootballPerl is like chess, only without the dice}	[reply]


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Re: Clean log_10 ?