Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

I have a line of input that looks something like:

RPC, rpc #001b, (1987)

I'm attempting to strip the year from inside the parenthesis. The code is:

($remainder, $working) =~ split(/\s\(/, $inLine);

where $inLine is the above-referenced line. I was expecting to see the following after the split:

$remainder = RPC, rpc #001b,
$working = 1987)

However, $remainder contains the entirety of $inLine and $working is empty. What am I missing?