(zdog) Re: (2) Filling an array

You can eliminate the $i var by doing the following:

for (0 .. $#array) { print "$_ $array[$_]\n" }
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Also, I would think you'd be better off using one of the other suggestions like for() or the x operator rather than map() for efficiency reasons.

Zenon Zabinski | zdog | zdog7@hotmail.com

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Re: (zdog) Re: (2) Filling an array by spartan (Pilgrim) on Sep 10, 2001 at 19:50 UTC
++zdog `for (0 .. $#array) { print "$_ $array[$_]\n" }` I like that... very clean, to the point, and quite readable. The only reason I chose `map` was to flex an all too atrophied brain muscle. :) TMTOWTDI Very funny Scotty... Now PLEASE beam down my PANTS!	[reply] [d/l] [select]


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