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in reply to Filling an array

++dragonchild
I was inspired by your map example to do something like this instead:
$value=" 1 ";
@array=map {$_=$value} (1..100);
$i=0;
foreach (@array) {
print "$i $_\n";
$i++;
}

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The $i variable (used as an incrementer) and the foreach merely proves the map statement.
-spartan

Very funny Scotty... Now PLEASE beam down my PANTS!

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(zdog) Re: (2) Filling an array
by zdog (Priest) on Sep 07, 2001 at 04:27 UTC
    You can eliminate the $i var by doing the following:

    for (0 .. $#array) { print "$_ $array[$_]\n" }

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    Also, I would think you'd be better off using one of the other suggestions like for() or the x operator rather than map() for efficiency reasons.

    Zenon Zabinski | zdog | zdog7@hotmail.com

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      ++zdog
      for (0 .. $#array) { print "$_ $array[$_]\n" }
      I like that... very clean, to the point, and quite readable. The only reason I chose map was to flex an all too atrophied brain muscle. :)
      TMTOWTDI

      Very funny Scotty... Now PLEASE beam down my PANTS!
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