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Re: perl -e hash assignment and range operator bugby Rudif (Hermit)
|on Aug 27, 2001 at 01:31 UTC||Need Help??|
>> So I test it out, like i do everything, and i do: perl -e"%a=( 1..10, 11..20 );print keys %a" and I get no output.
Well, when I test in on my one and only Perl (5.6.1 build 628 on Win2k), I get this
or in a more readable version
both of which look good to me.
>> So now I says to me, this must be a bug, and to confirm, i try:
which yields nada, and then ...
Me again, when I test it, I get this - as expected.
Seems to work nicely. The % character that japhy mentioned is tucked inside the double quotes and is seen by Perl, not the cmd shell.
So where is the problem? Did I miss something here?
I am all for bashing the cmd shell (pun intended) when justified, but here I cannot confirm the problem.
Can you help me out on this, crazyinsomniac ?
Update Could somemonk please set me straight on the operator precedence in the second example above?
I think that the assignment binds 1..10 to %a, whereas 2..11 has no effect other than being the return value from the comma operator, which is thrown away. Is this correct?