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Operator precedenceby muba (Priest) |
on Jan 12, 2013 at 23:01 UTC ( [id://1013066]=perlquestion: print w/replies, xml ) | Need Help?? |
muba has asked for the wisdom of the Perl Monks concerning the following question: According to perldoc perlop, terms have the highest precedence of everything: A TERM has the highest precedence in Perl. They include variables, quote and quote-like operators, any expression in parentheses ... Please consider the following code.
Given that expressions in parentheses have topmost priority, one would expect Perl to evaluate (banana || cherry) first, which would boil down to say "banana" which would return 1, and only then to evaluate apple && (1). So the output I more or less expected is:
However, the output I get is:
Please shed some light on this. Why isn't the parenthesed expression evaluated first? I understand the short circuiting nature of the logical operators — for one, this explains why cherry isn't outputted at all, but I fail to understand how && seems to have higher precedence than ( EXPR ), despite the information in the documentation.
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