Coming soon: Algorithm::Loopsby tye (Sage)
|on Apr 11, 2003 at 21:35 UTC||Need Help??|
Now you can write arbitrarilly-nested loops easily.
Today in the CB, artist proposed a "math"1 puzzle (heavily paraphrased by me): Find a set of numbers where each is composed of the exact same set of digits just in different orders, such that the numbers sum to 2003. For example, if I had asked about 2070, you would tell me 2070 = 198+891+981.
I fairly quickly threw together some code to search for a solution. I decided that adding 1 together 2003 times was not interesting and neither was adding 2003 up once. I didn't want to allow leading zeros nor repeated digits and I wanted the digit orders to be different for each number so I knew I only had to worry about picking 3 digits:
which I combined with Permuting with duplicates and no memory to produce:
So, no "good" solution for 2003. So I started widening the search by allowing zeros, repeated digits, repeated orderings (by simply changing "0" to "1" and dropping a few "+1"s). Still no solution.
So, since I was allowing repeated orderings, maybe I should add up more than 3 numbers. So I changed the code to add up 4 numbers and found:
And then I went D'Oh!. I should have been allowing up to 6 numbers and not allowing duplicates. So the inner loops got rather complicated:
and so I thought I'd turn it into a iterator similar to how I do things like (tye)Re: getting my neighbours in an N-dimensional space so that I could play with 4-digit numbers etc. without having to change the code, adding more loops and more $z, $w, $v, etc. variables.
But this one-off code had just been so easy to write. Making an iterator was going to be a bit tricky... I should write something to make writing the iterator nearly as easy as the one-off code...
This resulted in what I think is perhaps the neatest 30-odd lines of Perl code that I've ever written (but the blush will surely come off the rose after a bit of time passes).
This code lets you write arbitrarilly nested loops so that you can switch between having loops nested 6 deep or nested 4 deep without modifying any code. I think I'll upload it to CPAN as Algorithm::Loops (or Algorithm::NestedLoops) before long.
and you use it like so (showing both how to use it to get an iterator and how to use it with a call-back):
with parts of the code that you might want to swap in (to find "interesting" things) commented with "##".
And, yes, I did find exactly one "good" solution for 2003. With the code provided, you can too.
I think artist should go back to the person who provided this puzzle and offer a counter puzzle: I wanted to give you this puzzle using a number other than 2003 but make it as hard as possible while still only using 3-digit numbers in the solution. I came up with exactly two candidates to replace 2003. What were they? (:
1 I've had math teachers get mildly annoyed when "math" is used when "arithmatic" is more appropriate, hence the quotes.