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Re: Re: Re: (jeffa) Re: A better mod (%) operator?

by jmcnamara (Monsignor)
on Jul 09, 2002 at 08:46 UTC ( #180428=note: print w/replies, xml ) Need Help??

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  1. or download this
        @a = 1 + 2;
    $a = 1 + 2;
  2. or download this
        $x = (1,2,3);
    print $x;     # prints 3

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