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in reply to My day with Damian Conway

So in Perl 6 the existing ... range operator will die?

Well, I think nobody is using anyway.

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Re: My day with Damian Conway
by Abigail (Deacon) on Jun 26, 2001 at 03:50 UTC
    Why would it have to die? One is a language contruct (or if you want, an operator with 0 operands), the other (the existing operator) is a binary infix operator. There cannot be any ambiguity.

    -- Abigail

[reply]

      So, if I wasn't sure whether I wanted to use .. or ... as my range operator (because I hadn't recently read up on the differences), I'd just mark that part of the code as unfinished by typing: pre()...post() then later replace it with the correct range operator after I'd had time to do that research. q-:

              - tye (but my friends call me "Tye")
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