in reply to Re: Strange regex to test for newlines: /.*\z/
in thread Strange regex to test for newlines: /.*\z/
I am not quite agreeable to the statement about what '.*' should match.
For my understanding '.' should ignore newlines always but if the operator /s is used. That means that '.+' and '.*' are just multiple searches of '.' and should still ignore newlines.
Now I understand $ and \z as the following... $ means to matches both the end and the newline before - quote perldoc - and \z only the end but not the newline.
For my understanding '.' should ignore newlines always but if the operator /s is used. That means that '.+' and '.*' are just multiple searches of '.' and should still ignore newlines.
Now I understand $ and \z as the following... $ means to matches both the end and the newline before - quote perldoc - and \z only the end but not the newline.
print "foo matched\n" if "foo\n" =~ /^foo$/; print "bar matched\n" if "bar\n" =~ /^bar$ \n/x; # $ before end or newline print "baz doesn't matched\n" if "baz\n" !~ /^baz\z/; print "foobar matched\n" if "foobar\n" =~ /^foobar\n\z/; # \z after newline print "match foo\n" if "foo\n" =~ /.*$/; # .* ignore newline and $ is before newline print "doesn't match bar\n" if "bar\n" !~ /.*\z/; # .* ignore newline and \z is after newline print "match baz\n" if "baz\n" =~ /.?\z/; # but what the hell happends here? for ( qr/(.?)\n\z/, qr/(.?)\z/ ) { "hello world\n" =~ $_; print "-$1-\n"; } -d- --It seems that '.?' ignore the newline as expected and search on after the newline with '.?\z', because it searches _until_ '\z'. Also it seems that '.*' matches until the newline and not between '\n' and '\z'. '.*' is greedy, '.?' not. Maybe I missunderstand it.
|
---|
Replies are listed 'Best First'. | |
---|---|
Re^3: Strange regex to test for newlines: /.*\z/
by xicheng (Sexton) on May 22, 2007 at 18:17 UTC |
In Section
Seekers of Perl Wisdom