in reply to Sorting colon-delimited records

First of all, those are colons, not semicolons. ;-) Sounds like a good place for a Schwartzian Transform by our own merlyn:
#!/usr/bin/perl use strict; use warnings; my @data = <DATA>; chomp @data; my @sorted = map { $_->[0] } sort { $a->[1] cmp $b->[1] } map { [ $_, (split /:/)[1] ] } @data; print "data = \n@data\n"; print "sorted = \n@sorted\n"; __DATA__ area1:place1:name1 area1:place4:name2 area3:place3:name3 area5:place2:name2
data = area1:place1:name1 area1:place4:name2 area3:place3:name3 area5:place2: +name2 sorted = area1:place1:name1 area5:place2:name2 area3:place3:name3 area1:place4: +name2
Update:For more information on the Schwartzian Transform, read Tom Christiansen's "Far More Than Everything You've Ever Wanted To Know About Sorting" paper.
Update 2:Changed example data to make it more obvious what was going on.

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Re: (RhetTbull) Re: Sorting comma-delimited records
by venki (Acolyte) on May 31, 2002 at 18:33 UTC
    thanks. Great help! I really appreciate your timely help guys