Re^2: regexp list return 5.6 vs 5.8

Do you really get [[] in the first print statement? If so, any idea how (output of first 2 print's is [] with perl 5.8.7 on CentOS 5)?

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Re^3: regexp list return 5.6 vs 5.8 by hipowls (Curate) on Jan 24, 2008 at 09:34 UTC
Really, I too was surprised. Changing sub test to `sub test { my @rv = $_[0] =~ /^([0-9]+)$/; print "<<@rv>>\n"; return @rv[ 0 .. $#rv ]; }` [download] produced `<<>> [[] <<>> [] <<123>> [123] <<123>> [123]` [download] changing sub test to `sub test { my @rv = $_[0] =~ /^([0-9]+)$/; print "<<@rv>>\n"; return wantarray? @rv: $rv[-1]; }` [download] produces `michael$ perl t.pl <<>> Use of uninitialized value in print at t.pl line 5. [] <<>> [] <<123>> [123] <<123>> [123]` [download] Note the warning. (And I suspect there are some monks who are now saying I told you so;-)	[reply] [d/l] [select]
Re^4: regexp list return 5.6 vs 5.8 by Sixtease (Friar) on Jan 24, 2008 at 09:50 UTC
Wow, so the `[[]` was not a typo? I thought it was. I still don't understand how it could have got there! What does it print when you use different delimiters? (like `print "{", scalar(test('abc')), "}";`) use strict; use warnings; print "Just Another Perl Hacker\n";	[reply] [d/l] [select]
Re^5: regexp list return 5.6 vs 5.8 by hipowls (Curate) on Jan 24, 2008 at 10:21 UTC
Strange indeed. `michael$ perl t.pl {{} {} {123} {123}` [download]	[reply] [d/l]
Re^6: regexp list return 5.6 vs 5.8 by johngg (Canon) on Jan 25, 2008 at 10:15 UTC