Output PHP

kmiles has asked for the wisdom of the Perl Monks concerning the following question:

Hi Monks, I have several new web sites that use PHP heavily (all of our existing sites use Perl). All I want to be able to do is create a PHP template for output from a Perl program. Template is created, slurp the template into $var, replace with content using regexp, then print STDOUT "Content-type: text/html\n\n$var\n"; Problem is that <?php commands ?> are ignored when dumped this way. I've written the contents to a temp file and then output a html redirect, which works but is very messy and slow. Is there a way to output to STDOUT but have the PHP processed? Thanks for any help!

Comment on Output PHP

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Re: Output PHP by rafl (Friar) on Jan 09, 2008 at 03:53 UTC
Maybe the PHP::Interpreter module can help you.	[reply]
Re^2: Output PHP by olus (Curate) on Jan 09, 2008 at 11:35 UTC
There's an article on that subject on Linux Journal. Integrating PHP and Perl	[reply]
Re^2: Output PHP by kmiles (Initiate) on Jan 09, 2008 at 17:53 UTC
I've looked at this also. I just haven't been able to figure out how to use it for this case. I was hoping someone could provide an example.	[reply]
Re: Output PHP by Cody Pendant (Prior) on Jan 09, 2008 at 06:06 UTC
Direct system() or exec() call to the PHP executable? Their -r flag looks like it's the equivalent of our -e flag so maybe `system("php -r $var")` [download] would do it? Nobody says perl looks like line-noise any more kids today don't know what line-noise IS ...	[reply] [d/l]
Use Perl to output PHP template by kmiles (Initiate) on Jan 10, 2008 at 16:21 UTC
I posted this question the other day http://perlmonks.org/index.pl?node_id=661239 Thanks for the responses. I was able to use LWP::Simple to capture the output of the PHP template to a Perl $var, then do my regexp content replacement inside the $var, then output all to STDOUT.	[reply]

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