Re^4: return +0

Just note that -.0 is distinct from .0.

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Comment on Re^4: return +0

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Re^5: return +0 (-.0?) by tye (Sage) on Nov 27, 2007 at 22:10 UTC
Perhaps you could be less vague. There is no such distinction in my tests: `> perl -MDevel::Peek -e"Dump(+.0)" SV = NV(0xa4a5fc) at 0x3d53c4 REFCNT = 1 FLAGS = (PADBUSY,PADTMP,NOK,READONLY,pNOK) NV = 0 > perl -MDevel::Peek -e"Dump(-.0)" SV = NV(0xa4a60c) at 0x3d53f4 REFCNT = 1 FLAGS = (PADBUSY,PADTMP,NOK,READONLY,pNOK) NV = 0 > perl -MDevel::Peek -e"Dump(.0)" SV = NV(0xa4a5fc) at 0x3d53c4 REFCNT = 1 FLAGS = (PADBUSY,PADTMP,NOK,READONLY,pNOK) NV = 0` [download] - tye	[reply] [d/l]
Re^6: return +0 (-.0?) by Sidhekin (Priest) on Nov 28, 2007 at 22:23 UTC
It depends on the math libraries? They're different here, at least: `sidhekin@blackbox[23:22:41]~$ perl -MDevel::Peek -le 'Dump(.0)' SV = NV(0x816e490) at 0x814dce4 REFCNT = 1 FLAGS = (PADBUSY,PADTMP,NOK,READONLY,pNOK) NV = 0 sidhekin@blackbox[23:22:51]~$ perl -MDevel::Peek -le 'Dump(-.0)' SV = NV(0x816e4a0) at 0x814dd20 REFCNT = 1 FLAGS = (PADBUSY,PADTMP,NOK,READONLY,pNOK) NV = -0 sidhekin@blackbox[23:22:53]~$` [download] `print "Just another Perl ${\(trickster and hacker)},"` The Sidhekin proves Sidhe did it!	[reply] [d/l] [select]