in reply to last in a do while loop

does not compile, since the do does not know anything about the while.
~/perl$ cat x do { charlie; last if bob; david; } while (alice); ~/perl$ perl -c x x syntax OK ~/perl$ perl -v This is perl, v5.6.1 built for i386-linux
So it compiles just fine.

What is not working, though, is the last. This is because the block introduced with do is neither a loop nor a bare block. Your statement is basically equivalent in structure to print foo while bar.

What you can do instead is a bare block, because you can use next, last, redo on a bare block:

LOOP: { charlie; last LOOP if bob; david; redo LOOP if alice; }

-- Hofmator

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