in reply to Re^3: Shortcut operator for $a->{'b'}=$b if $b;

in thread Shortcut operator for $a->{'b'}=$b if $b;

Maybe someone can suggest how to define a '?=' operator

`$a->{'b'} ?= $b;`

assigns $b to $a->{'b'} if $b is defined, does not autovivify $a->{'b'} if $b not defined

is that possible? - I'm thinking of `use overload` but I dimly recall that there is a finite set of operators you can overload and ?= isnt one of them.

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