in reply to Re^3: Shortcut operator for $a->{'b'}=$b if $b;
in thread Shortcut operator for $a->{'b'}=$b if $b;

Maybe someone can suggest how to define a '?=' operator

$a->{'b'} ?= $b;

assigns $b to $a->{'b'} if $b is defined, does not autovivify $a->{'b'} if $b not defined

is that possible? - I'm thinking of use overload but I dimly recall that there is a finite set of operators you can overload and ?= isnt one of them.

...reality must take precedence over public relations, for nature cannot be fooled. - R P Feynmann