in reply to Perl Idioms Explained - && and || "Short Circuit" operators
Now you know why Perl doesn't have a switch statement . . .
It should still get one, since the advantage of C switches it that they have O(1) efficency, whereas most of the equivilent idioms in Perl have O(n) worst-case time. <UPDATE>Actually, the one posted above always runs in O(n) time.</UPDATE> <UPDATE2>Oops, that update wasn't quite true. Thanks demerphq.</UPDATE2> You can get O(1) time using a hash table that stores subroutine refs, but then you make implementing fall-through a lot harder.
Fortunatly, we're getting a real switch in Perl6.
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I wanted to explore how Perl's closures can be manipulated, and ended up creating an object system by accident.
-- Schemer
:(){ :|:&};:
Note: All code is untested, unless otherwise stated