in reply to ASCII Pattern - Golf

I can get 83:
$i=9;do{print((map{(sort map{abs}$_-$ARGV[0],$i-$ARGV[1])[-1]}1..9),"\ +n")}while--$i


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Re: Re: ASCII Pattern - Golf (Russ: 77)
by Russ (Deacon) on Sep 19, 2003 at 02:57 UTC
    Okay, now 77 (if you don't miss the trailing newline):
    $i=9;do{print"\n",map{(sort abs$_-$ARGV[0],abs$i-$ARGV[1])[-1]}1..9}wh +ile--$i


      74 :)
      $i=9;do{print$/,map{(sort abs$_-$ARGV[0],abs$i-$ARGV[1])[1]}1..9}while +--$i

        A for-loop is usually shorter than a do{...}while-loop. 70 :-)


        If you want the newlines "right", I end up at 72:

        $t=abs$ARGV[1]+$_,print map((sort$t,abs$ARGV[0]-$_)[1],1..9),$/for-9..-1

        Update: Well, what do you know ... the string $ARGV[1]+$_ is longer than the strings ($s=pop) and $s taken together. Make those 69 and 71 (both with tie-breaker at 30 different characters):


        ... and ...

        $t=abs,print map((sort$t,abs$ARGV[0]-$_)[1],1..9),$/for($s=pop)-9..$s-1

        The Sidhekin
        print "Just another Perl ${\(trickster and hacker)},"