Parsing Apache Log to Get Most Recent File Access

enoch has asked for the wisdom of the Perl Monks concerning the following question:

I am writing a quick script that will parse over my Apache access log and print out the most recent file accesses. The gotcha comes in with the fact that I want it to only print out the most recent file accessed from each unique IP, and I want the output sorted by date.

Here is my code:

#!/usr/bin/perl
use warnings;
use strict;

use Date::Manip;

use vars qw(%ipHash);

while(<DATA>)
{
    /    ^((\d{1,3}\.){3}\d{1,3})    # grab the IP address into $1
        \s\-\s\-\s\[
        (\d\d\/\w{3}\/\d\d(\d\d\:){3}\d\d)    # grab the date into $3
        \s\-\d{4}\]\s"\w{1,4}\s
        ([\/|\w|\.|_]+)        # grab the file path into $5
    /x 
        and $ipHash{&UnixDate($3,"%s")} = [$1, $3, $5];
}

print join "\n", 
    map 
        {$ipHash{$_}[0] . " => " . $ipHash{$_}[1] . "\t" . $ipHash{$_}
+[2]} 
    sort keys %ipHash;

__DATA__
209.36.83.252 - - [17/Oct/2002:05:53:17 -0400] "GET /scripts/..%%35%63
+../winnt/system32/cmd.exe?/c+dir HTTP/1.0" 400 303
209.36.83.252 - - [17/Oct/2002:05:53:17 -0400] "GET /scripts/..%%35c..
+/winnt/system32/cmd.exe?/c+dir HTTP/1.0" 400 303
209.36.83.252 - - [17/Oct/2002:05:53:17 -0400] "GET /scripts/..%25%35%
+63../winnt/system32/cmd.exe?/c+dir HTTP/1.0" 404 313
209.36.83.252 - - [17/Oct/2002:05:53:17 -0400] "GET /scripts/..%252f..
+/winnt/system32/cmd.exe?/c+dir HTTP/1.0" 404 313
68.9.44.75 - - [17/Oct/2002:06:50:34 -0400] "GET /phpMyAdmin HTTP/1.1"
+ 301 322
68.9.44.75 - - [17/Oct/2002:06:50:34 -0400] "GET /phpMyAdmin/ HTTP/1.1
+" 200 898
68.9.44.75 - - [17/Oct/2002:06:50:36 -0400] "GET /phpMyAdmin/left.php?
+lang=en-iso-8859-1&convcharset=iso-8859-1&server=1 HTTP/1.1" 200 1024
129.22.39.158 - - [17/Oct/2002:18:05:10 -0400] "OPTIONS / HTTP/1.1" 20
+0 0
160.79.211.121 - - [17/Oct/2002:19:51:31 -0400] "GET /default.ida?NNNN
+NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNN
+NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNN
+NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNN
+NNNNNNNNNNNNN%u9090%u6858%ucbd3%u7801%u9090%u6858%ucbd3%u7801%u9090%u
+6858%ucbd3%u7801%u9090%u9090%u8190%u00c3%u0003%u8b00%u531b%u53ff%u007
+8%u0000%u00=a  HTTP/1.0" 400 303
129.22.82.8 - - [17/Oct/2002:20:37:10 -0400] "GET /index.php HTTP/1.1"
+ 200 25430
129.22.82.8 - - [17/Oct/2002:20:37:10 -0400] "GET /index.php?=PHPE9568
+F35-D428-11d2-A769-00AA001ACF42 HTTP/1.1" 200 4440
129.22.82.8 - - [17/Oct/2002:20:37:10 -0400] "GET /index.php?=PHPE9568
+F34-D428-11d2-A769-00AA001ACF42 HTTP/1.1" 200 2962
129.22.82.8 - - [17/Oct/2002:21:25:44 -0400] "GET / HTTP/1.1" 200 2673
129.22.82.8 - - [17/Oct/2002:21:25:44 -0400] "GET /manual/images/apach
+e_pb.gif HTTP/1.1" 404 302
[download]

That code produces the following output:

209.36.83.252 => 17/Oct/2002:05:53:17   /scripts/..
68.9.44.75 => 17/Oct/2002:06:50:34      /phpMyAdmin/
68.9.44.75 => 17/Oct/2002:06:50:36      /phpMyAdmin/left.php
160.79.211.121 => 17/Oct/2002:19:51:31  /default.ida
129.22.82.8 => 17/Oct/2002:20:37:10     /index.php
129.22.82.8 => 17/Oct/2002:21:25:44     /manual/images/apache_pb.gif
[download]

Now, ideally, I would not want the IP's repeated. Rather, I just want to see the last file accessed by that IP. So, the output would look like:

209.36.83.252 => 17/Oct/2002:05:53:17   /scripts/..
68.9.44.75 => 17/Oct/2002:06:50:34      /phpMyAdmin/
160.79.211.121 => 17/Oct/2002:19:51:31  /default.ida
129.22.82.8 => 17/Oct/2002:21:25:44     /manual/images/apache_pb.gif
[download]

But, to maintain my sorting by date, I key the hash by the Unix timestamp and not the IP. Would I need to set up a dualing hash thing so I can sort by date but keep only one entry for each IP address? I just can't seem to wrap my head around this and wondered if any monks had some nifty ideas.

Thanks,
enoch

P.S. You gotta love those 'default.ida?NNNNNNN' entries.

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