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in reply to regexp - how to embed a "/" within the executable part of the regexp when using /e

You could also do it without division. 
$_ = '22C';
s/(\d+)C/($1*9*.2)+32 . "F"/ge;
print;
print "\n";

$_ = '0C';
s/(\d+)C/($1*9*.2)+32 . "F"/ge;
print;
print "\n";

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