in reply to Getting information about a remote file via SSH: how to escape the filename

$ssh->cmd(qq[ls -l $remotefile]); # Then parse the info I want from $stdout with an easy regex

But I can't rule out the possibility that the remote filename might contain shell metacharacters.

This should do it: $ssh->cmd(qq[ls -l "$remotefile"]);

Cheers, Sören

(hooked on the Perl Programming language)