print //;       # prints 1, scalar return val of match null in $_ (always true)
print \//;      # SCALAR(0x....)
print \\//;     # ditto
print \\\//;    # ditto
print \\\\//;   # ditto
etc...


# thus what you are saying is divide the scalar value
# of one memory reference by another

print  \\//   /   \\\//
       ref   div   ref

##</code><code>##

$a = \1; # first ref in lower mem
$b = \1; # second ref in slightly higher mem 
print $b/$a;

# prints 1.00000684833673